The liquid-phase dimerization of C5H6, 2 C5H6 C10H12(l), is studied at a certain

Question

The liquid-phase dimerization of C5H6, 2 C5H6 C10H12(l), is studied at a certain temperature, giving the following data: Time (s) [C5H6] (M) 0.0e+00 0.100 1.0e+02 0.0254 2.0e+02 0.0146 3.0e+02 0.0102 4.0e+02 0.00786 Figure out whether this reaction is first-order or second-order with respect to the concentration of C5H6. Calculate the value of the rate constant. Pick the choice from below which gives the correct reaction order and value of the rate constant for this reaction. a) This reaction is second-order with the rate constant k = 5.86e-02 M-1 s-1. b) This reaction is first-order with the rate constant k = 5.86e-01 s-1. c) This reaction is second-order with the rate constant k = 2.93e-01 M-1 s-1. d) This reaction is first-order with the rate constant k = 1.76e+00 s-1. e) This reaction is first-order with the rate constant k = 7.33e-02 s-1. Can you please explain how you got your answer!

Explanation / Answer

t cocn 0 0.1 1 0.0254 2 0.0146 3 0.0102 4 0.00786 we have to check for kinetics of different orders and confirm it. seeing pattern it looks like 2st order as change in concentration is high. lets check it k = (1/t) (1/a-x -1/a) k1 = (1/1) (1/0.0254- 1/0.1) = 29.37 k2 = (1/2) (1/0.0146 - 1/0.1) = 29.24 k3 = (1/3) (1/0.0102-1/0.1) = 29.34 so k values is constant and thus obeying 2nd order kinetics. hence order of reaction is 2. and k = 2.93 e^01 M-1s-1 option C is answer hence

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