k3[Fe(C2O4)3].3H2O the molar mass is 491 g/mol and what is the theoretical yield

Question

k3[Fe(C2O4)3].3H2O the molar mass is 491 g/mol and what is the theoretical yield by moles and gram and what is the %yield of k3[Fe(C2O4)3].3H2O if the mass of watch glass and k3[Fe(C2O4)3].3H2O is 34.07g and the mass of watch glass is 31.79g. Q1: using the moles of K3[Fe(C2O4)3].3H2O, calculate the theoretical yield, in grams, of K3[Fe(C2O4)3].3H2O. Q2/ show the calculation for the percent yield of K3[Fe(C2O4)3].3H2O using your actual yield and the theoretical yield

Explanation / Answer

theoretical moles of K3[Fe(C2O4)3)3.H3O can be calculated from the reaction 2Fe(C2O4).2H2) + H2C2O4 (aq) ---> 2K3[Fe(C2O4)3].3H2O if we have mass or moles of both reactants then mass or moles of product can be calculated. This calculated mass is theoretical yield experimental yield = 34.07-31.79 = 2.28 gm % yiled = 2.28/(theoretical yield in gm) x 100

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