Pentane, C_5H_12, is a hydrocarbon that is commonly used as a fuel for solvent.

Question

Pentane, C_5H_12, is a hydrocarbon that is commonly used as a fuel for solvent. a) Write a balanced chemical equation for the complete combustion of pentane. C_5H_12+8O_2-->5CO_2+6H_2O b) Calculate the volume of air at 26 degrees Celsius and 0.99 atmosphere that is needed to burn completely 14.34 grams of pentane. Assume that air is 21.0 percent O_2 by volume. c) When 1 mol of pentane is reacted with pure oxygen, O_2, -191 kJ of heat is released. Calculate the heat of formation, Hof, of pentane given that the Hof of H_2O(l) is -285.3 kJ mol-1 and Hof of CO_2(g) is -393.5 kJ mol-1. (Note: I expect you to calculate the Hof of pentane from the data in this problem.)

Explanation / Answer

1. a) C5H12+8O2==>5CO2 +6 H2O b) PV=nRT; plug in the numbers and i got 4.1L c) square root of (M2/M1); and you get18.04g; M= molar mass 2. a) 85.7g/12.011g = 7.136mol C 14.3g/ 1.008g = 14.1865mol H 7.136/7.136= 1(C) 14.1865/ 7.136= 2(H) CH2 b) 1.Molar Mass = dRT/P; 135.45g 2. 135.45/14.027= 9.656

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