how many oxygen atoms are there in 25.0 g of CaCo3? Solution plz rate Calcium Ca

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Explanation / Answer

plz rate Calcium Carbonate = CaCO3 ---> find the total molecular weight (has units of grams per mole) by adding the molecular weights of the atoms (look on a periodic table). Ca = 40.08g/mol, C = 12.01 g/mol O =16.00g/mol (Oxygen x3 =48g/mol) Sum = 100.09 grams per mole for CaCO3 Now take 25g/ 100.09 = 0.24978 moles of CaCO3 now multiply by Avagadro's Number, 6.02*10^23 which is particles per mole (or atoms, depending on if you're talking about a compound of not) So 0.24978 * 6.02e23 = 1.50365*10^23 particles.

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