The work done when a gas is compressed in a cylinder is 462 J; if there is a hea

Question

The work done when a gas is compressed in a cylinder is 462 J; if there is a heat transfer of 128 J to the surroundings, what is the energy change for the process? Please explain this question in detail to me because i am really lost Please do not answer if you are just going to answer the question if you are going to post a retarded answer on how i should learn thing ...because i am trying to learn how to do this and i have been trying to work it out all night. And my teacher made this an open class question not a homework question but i need to learn this for a test.

Explanation / Answer

The change of energy of the system, dU, is given by dU = dq + dw where dq is the change in heat of the system and dw is the change in work. Since work is done on the system, you are adding 462 J to it, but since heat is lost to the surroundings, you are removing 128 J from it: dU = -128 J + 462 J = 334 J

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