Suppose we have a population of 100 snapdragons, and the phenotypes are found in

Question

Suppose we have a population of 100 snapdragons, and the phenotypes are found in the following numbers: 44 Red (RR), 30 pink (=Rr), and 26 white (rr).

p = ((2*the number of RR since each has two R alleles) + the number of Rr since each has one R allele)) all divided by the total number of alleles, which equal 2 * the number of individuals in the population. = ((44*2) + 30))/200 = 0.59

What does q equal?

Hair color in mice shows complete dominance. Individuals that are BB and Bb have black hair; individuals that are bb have red hair. In your population of 100 mice, you find 16 individuals with red hair.

Calculate the following (assuming the population is in Hardy-Weinberg equilibrium): q = (Hint: remember that 16/100 = 0.16 is the frequency of recessive homozygotes = q2 ) p = (Hint: What does p + q equal?) The expected frequency of the AA genotype = The expected frequency of the Aa genotype = Rev. Fall 15 Section 3 – Simulation of Hardy-Weinberg Equilibrium Based on information provided in lecture, erect a testable hypothesis on changes in gene frequencies in ideal populations:

Using the data below, complete the table and answer the questions from your lab manual.

Do your data support your hypothesis? Explain any discrepancies.

Was the parent generation in Hardy-Weinberg Equilibrium? If not, how many generations did it take for Hardy-Weinberg Equilibrium to be reached?

Explanation / Answer

1. The frequency of q allele = 2* homozygous recessive+ heterozygous number/ 2* total population.

q = 2* 26 + 30/ 2* 100 ==> 0.41

Since, p+q = 1, p = 1-0.41 = 0.59.

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