An unknown white solid consists of two compounds. Part of the unknown mixture di

Question

An unknown white solid consists of two compounds. Part of the unknown mixture dissolved while the rest is insoluble in water. The solution with the dissolved unknown is treated with and yields a white precipitate. The remaining part of the original solid that was insoluble in water dissolves in with the evolution of carbon dioxide gas. The resulting solution is then treated with and yields a second white precipitate. Let the soluble compound in the unknown be represented by AB and the insoluble compound in the unknown be represented by XY My options for A,B, X,Y are: Na+ NH4+ SO4 ^-2 Ba+2 Mg+2 PO4 ^-3 CO3 ^-2 OH- How on earth do I start this?

Explanation / Answer

the insoluble compound in the unknown be represented by XY. the solid that was insoluble in water dissolves in HCl(aq) with the evolution of a gas: Carbonate treated with (NH4)2SO4(aq) and yields a second white precipitate...... Barium XY was BaCO3 ======================== Let the soluble compound in the unknown be represented by AB The solution is treated with KOH(aq) and yields a white precipitate.... magnesium or Barium the unknown mixture dissolved ..... sulfate of magnesium AB sounds like MgSO4

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.