Aluminum reacts with chlorine gas to form aluminum chloride via the following re

Question

Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: You are given 30.0 of aluminum and 35.0 of chlorine gas. Part A If you had excess chlorine, how many moles of of aluminum chloride could be produced from 30.0 of aluminum? Express your answer numerically in moles. Part B If you had excess aluminum, how many moles of aluminum chloride could be produced from 35.0 of chlorine gas, ? Express your answer numerically in moles

Explanation / Answer

2Al + 3Cl_2--->2AlCl_3 Moles Al = 30g / 26.9815 g/mol= 1.11 Here Al is the limiting reagent moles of aluminum chloride produced =1.11 b) moles Cl2 = 35g/70.906 g/mol =0.4936 here Cl2 is the limiting reagent 3 moles of Cl2 gives 2 moles of AlCl3 => 0.4936 would gives =0.329 moles of AlCl3

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