A 3.125 g sample of primary standard of Na2CO3 was treated with 40.00 mL of dilu

Question

A 3.125 g sample of primary standard of Na2CO3 was treated with 40.00 mL of dilute perchloric acid. The solution was boiled to remove CO2, following which the excess HClO4 was back-titrated with 10.12 mL of dilute NaOH. In a separate experiment, it was established that 27.43 mL of the HClO4 neutralized the NaOH in a 25.00 mL portion. Calculate the molarity of the NaOH solution. Hint: Solve this problem by considering the two equations: For the back-titration (1): total amount of perchloric acid: n1(HClO4) = 2n(Na2CO3) + n1(NaOH) For the acid-base titration (2): n2(NaOH) =n2(HClO4) A. 1.737 M B. 2.239 M C. 1.974 M D. 1.524 M

Explanation / Answer

Ans: 0.1799 M HClO4 ; 0.1974 M NaOH

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