Cyclopentadiede (C5H6) reacts with itself to form dicyclopentadiede (C10H12). A

Question

Cyclopentadiede (C5H6) reacts with itself to form dicyclopentadiede (C10H12). A 0.0400 M solution of C5H6 was monitored as a function of time as the reaction proceeded. The following data was collected.

C5H6 -> C10H12

Time (s) 0.0 50.0 100.0 150.0 200.0
[C5H6] (M) 0.0400 0.0300 0.0240 0.0200 0.0174
???
1. Determine the order of the reaction.

2. What is the value of the rate constant?

Conditions:
1. We will use a technique called Documented Problem Solutions (DPS). In DPS, the student will document each step involved in solving the problem. You will be graded by your explanation of each step taken as well as for the answer itself.

PLEASE SHOW ALL WORK AND EXPLANATIONS.

Explanation / Answer

initial conc = 0.04 =a one way of finding order is testing for values of k if we assume rxn is 2nd order and cal k for different values and if it attains to be constant then rxn is 2 nd order , lets assume its 2nd order k = 1/t [1/(a-x) -1/a ] k1 = (1/50)[1/0.03 - 1/0.04] = 0.166 k2 = (1/100) [1/0.024 -1/0.04] = 0.1666 so we observe k1= k2 = 0.01666 so k is obeying 2nd order eq , 1)hence order of rxn = 2 2) k = 0.1666

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