1. While you are roller-blading around Lake Artemesia in Greenbelt, you notice a

Question

1. While you are roller-blading around Lake Artemesia in Greenbelt, you notice a fascinating bark beetle on the trees. Glad for an excuse to catch your breath, you stop and observe that there are three different trophic behaviors in these beetles and you record the ratios of beetles with each of these behaviors. Being the biologist that you are, when you get home you dive into the literature and find the following genotypes are in the beetle population.

QQ (feeds under bark) 0.6

Qq (feeds on top of bark) 0.3

qq (feeds on leaves) 0.1

a) What are the allele frequencies and expected genotypic frequencies? Explain.

b) Is the population in Hardy Weinberg equilibrium? (NOTE: You do not need to analyze this statistically. Make a judgment based on the proportions).

c) If you answered “No” to b): List at least three biologically valid reasons why the observed beetle population may not be in equilibrium. If you answered “Yes” to b): Why do you think this might be the case?

2. In a sample of 75 corpse flowers from southeast Asia (Amorphophallus titanium the largest unbranched inflorescence in the world), three genotypes occurred in the following numbers. Calculate the genotypic and allele frequencies.

Genotype AA       Aa        aa

Numbers 43        21        11

7. Using the Hardy-Weinberg equation and data from the table above, determine the number of mice with the DD and Dd genotypes on found on both the light granite substrate and the dark lava substrate.

Use the values you just determined to answer the following questions.  

a). Which fur color seems to have the greatest overall selective advantage?

b). What might be some reasons for this advantage?

Explanation / Answer

1.

a. The allele frequency is determined by p2+2pq+q2

As per the question, The 2 alleles are Q and q

So rewriting the equation to Q2+2Qq+q2

Given that QQ or Q2 = 0.6, So Q will be Q= 0.774

Givent that qq or q2= 0.1 So, q= 0.316

Genotypic frequencies are

QQ= 0.774x 0.774= 0.6

Qq= 2pq= 2 x 0.7x 0.3= 0.4

qq= 0.316 x 0.316= 0.1

b. For the The population to be in hardy weinberg equilibrium p+q should be equal to 1 . p+q = 1 i.e Q+q = 1

But in this question, Q+q > 1

0.774+0.316 = 1.09 which is greater than 1

So, the population is not in hardy weinberg equilibrium.

c) The reasons for the population to not be in hardy weinberg equilibrium are - mutations, gene flow, genetic drift, non-random mating and natural selection.

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