9)Dintrogen tetraxide partialily decomposes according to the tollowing quium 100

Question

9)Dintrogen tetraxide partialily decomposes according to the tollowing quium 1000-L flask is charged with 920-1r-3 mol of NoOs Al equlbrium 5.9-1-3 mot of No0s remains Kfor this reaction is INSTR 1-This (50 - A) 0212 B) 0.197 C)694-10- D) 0.183 E)296-10-5 10) What volume of 0 716 M KBr solution is needed to provide 13.0 g of KBn A) 931 mL B) 185mL C) 153mL D) 655 ml 11) At high temperatures boron carbide vaporizes according to the equation Which equation describes the relationship between AG and &G; for this reaction? CAG-AG-4RTInp 2) AG AG for a reaction B) at STP D) at the start of the reaction 13) IfAG. is negative ,or a reaction C) K is between O and 1 14) Which sotution will be the most basic? A) 0 10 M CH OH B) 0 10 M H20 C) 010M Ba(OH)2 D) 0 10 M KOH E) All solutions have equal basicity 15) What is the pH of a solution prepared by diluting 25.00 mL of o 10 M HCI with enough water to produce a total volume of 100.00 mL A) 1.00 B) 1.60 C)3.20 D) 200 6) What is the pH of a 0 020 M Ba(OH02 solution? A) 12.60 B) 1230 C)1.70 D) 140

Explanation / Answer

Q9

initially

[N2O4] = 9.2*10^-3

[NO2] = 0

in equilbirium

[N2O4] = 9.2*10^-3 - x

[NO2] = 0 + 2x

and we know

[N2O4] = 9.2*10^-3 - x = 5.98*10^-3

x = 9.2*10^-3- 5.98*10^-3 = 0.00322

[NO2] = 0 + 2x = 2*0.00322 = 0.00644

Keq = [NO2]^2/[N2O4]

Keq = (0.00644^2)/(5.98*10^-3) = 0.0069353

K = 6.9*10^-3

nearest answer is C

Q10

M = mol/V

V = mol/M

V = (mass/MW)/M

V = (13/119.002 )/0.716)

V = 0.152572 L

V = 152.5 mL

choose c

Related Questions

Navigate

• Browse (All)
• Browse 9
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.