rses This Course Question 32 Calculate the temperature, in K, of 2.20 moles of g

Question

rses This Course Question 32 Calculate the temperature, in K, of 2.20 moles of gas occupying 3.70 L at 3.12 atm. Select one O A 28.0 K Marked out of 1.00 B.-209 K o C. 337 K D, 64.0 K Question 33 Not yet answered Marked out of 1 .00 Select one: Which of the following (with specific heat capacity provided) would show the largest temperature change upon gaining 200.0 J of heat? O A 500 g Zn, C0.39 Jig c B. 25.0 g Au, C0.128 Jg'C OC, 25.0 g sand. C..d=084 J/g°C D 25.0 g Ag C 0.235 Jig c E. 500 g ethanol, C 2.42 Jig C

Explanation / Answer

Ans 32 : D) 64.0 K

The temperature can be calculated using the ideal gas law , pV = nRT

Putting all the values we get :

3.12 x 3.70 = 2.20 x 0.0821 x T

T = 64.0 K

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