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n to the Ideal Gas Law outside is 11 C, and the air pressure is 0 800 atm. Your

ID: 592948 • Letter: N

Question

n to the Ideal Gas Law outside is 11 C, and the air pressure is 0 800 atm. Your neighbor,who released he balloon, tells you that he filed it with 4.10 moles of gas What is the volume of gas inside this baloon? apply the ideal gas law to problems involving temperature ressure, volume, and moles of a gas The variable R is known as the universal gas constant and has of R, use units of atmospheres for pressure, lbers for volume, and keivins for temperature A16.0L gas cyinder is filed with 7 80 moles of gas. The tank is stoned at 29 C. What is the pressure in the tark? P,-.1 Value latm 220. L kin is used for viaritying ceramics t is confines of at 1115 C and the 1 3

Explanation / Answer

Part A

To caculate volume of baloon use ideal gas equation

We know that PV = nRT

V = nRT/P

n = 4.10 mole,

T = 110C = 11+273.15 = 284.15K,

P= 0.800 atm,

R = 0.08205 L atm mol-1 K-1 ( R = gas constant)

V = ?

Substitute these value in above equation.

V = 4.10 X 0.08205 X 284.15/0.800 = 119.49 L

Volume of baloon = 119.49 liter

Part B

to calculate pressure of tank use ideal gas equation

Ideal gas equation

PV = nRT             where, P = atm pressure= ?

V = volume in Liter = 16 L

n = number of mole = 7.60 mol

R = 0.08205L atm mol-1 K-1 =Proportionality constant = gas constant,

T = Temperature in K = 290C = 27.15+ 29 = 302.15 K

We can write ideal gas equation

P = nRT/V

Substitute value in above equation

P = 7.60 X0.08205 X 302.15 / 16 = 11.78 atm

pressure in tank = 11.78 atm

Part C

use ideal gas equaion to calculate mole of gas

Ideal gas equation

PV = nRT             where, P = atm pressure= 1.025 atm,

V = volume in Liter = 220 L

n = number of mole = ?

R = 0.08205L atm mol-1 K-1 =Proportionality constant = gas constant,

T = Temperature in K = 11150C = 273.15+ 1115 = 1388.15 K

We can write ideal gas equation

n = PV/RT

Substitute the value

n = (01.025X 220) / (0.08205 X 1388.15) = 1.98 mole

mole of gas = 1.98 mole