2. Using the ideal gas equation, determine the number of moles present in a gas

Question

2. Using the ideal gas equation, determine the number of moles present in a gas if it has a pressure of 2.07 atm, a volume of 1.28 L and a temperature of 46.8 oC. Enter your answer in standard notation. Do not use scientific notation.
6.What is the value of the ideal gas constant in SI units? Give your asnwer to 3 decimal places. Do not include units, just the number.
7.When considering the gas laws, the Kelvin temperature scale must be used. The reason for this is that the Kelvin scale is directly proportional to the Kinetic Energy of the paricles, while the centigrade and fahrenheit scales are not. If you double the temperature of a gas, the pressure will double if volume is held constant. This makes sense if we consider that the particles will be striking the sides of the container with twice as much energy. Let's say we want to double 10o C. The answer would not be 20oC; rather, it will be 293 oC. 10oC is 283 K ( K = oC + 273). Doubling 283K gives 566K. Converting back to oC gives 293oC. What is the temperature in celcius if we double -16 oC?
8.Last week you reacted magnesium with a hydrochloric acid aqueous solution and hydrogen gas was produced. Let's say that you collected the gas given off by the reaction and measured it's pressure as 99.7 kPa. If the vapor pressure of water is 33.5 kPa at this temperature, then what is the pressure of the hydrogen gas? 2. Using the ideal gas equation, determine the number of moles present in a gas if it has a pressure of 2.07 atm, a volume of 1.28 L and a temperature of 46.8 oC. Enter your answer in standard notation. Do not use scientific notation.
6.What is the value of the ideal gas constant in SI units? Give your asnwer to 3 decimal places. Do not include units, just the number.
7.When considering the gas laws, the Kelvin temperature scale must be used. The reason for this is that the Kelvin scale is directly proportional to the Kinetic Energy of the paricles, while the centigrade and fahrenheit scales are not. If you double the temperature of a gas, the pressure will double if volume is held constant. This makes sense if we consider that the particles will be striking the sides of the container with twice as much energy. Let's say we want to double 10o C. The answer would not be 20oC; rather, it will be 293 oC. 10oC is 283 K ( K = oC + 273). Doubling 283K gives 566K. Converting back to oC gives 293oC. What is the temperature in celcius if we double -16 oC?
8.Last week you reacted magnesium with a hydrochloric acid aqueous solution and hydrogen gas was produced. Let's say that you collected the gas given off by the reaction and measured it's pressure as 99.7 kPa. If the vapor pressure of water is 33.5 kPa at this temperature, then what is the pressure of the hydrogen gas?
6.What is the value of the ideal gas constant in SI units? Give your asnwer to 3 decimal places. Do not include units, just the number.
7.When considering the gas laws, the Kelvin temperature scale must be used. The reason for this is that the Kelvin scale is directly proportional to the Kinetic Energy of the paricles, while the centigrade and fahrenheit scales are not. If you double the temperature of a gas, the pressure will double if volume is held constant. This makes sense if we consider that the particles will be striking the sides of the container with twice as much energy. Let's say we want to double 10o C. The answer would not be 20oC; rather, it will be 293 oC. 10oC is 283 K ( K = oC + 273). Doubling 283K gives 566K. Converting back to oC gives 293oC. What is the temperature in celcius if we double -16 oC?
8.Last week you reacted magnesium with a hydrochloric acid aqueous solution and hydrogen gas was produced. Let's say that you collected the gas given off by the reaction and measured it's pressure as 99.7 kPa. If the vapor pressure of water is 33.5 kPa at this temperature, then what is the pressure of the hydrogen gas?

Explanation / Answer

2)pv=nRt

R=0.082 atm L/ K mol

from solving number moles =0.0998

6)8.314 J/K mol

8)66.2 k pa

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