Lab 12 Stoichiometry Name Section Date Prelab Questions 1. Why do you want to ke
ID: 592528 • Letter: L
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Lab 12 Stoichiometry Name Section Date Prelab Questions 1. Why do you want to keep the hydrochloric acid to a minimum? 2. Give four guidelines for heating a test tube containing a liquid. 3. Write the balanced chemical equation (with state descriptors) for the reaction between sodium carbonate and hydrochloric acid. ced chemical equation (writh state descriptors) for the reaction between sodium bicarbonate and hydrochloric acid 5. Convert 0.73 g of sodium carbonate to moles (0.0069 mol) 6. Convert 0.65 g sodium bicarbonate to moles. (0.0077 mol) 7. What volume, in liters, is occupied by 0.0083 mol of carbon dioxide at 745.6 mmHg and 20.0°C? (0.20 L) Instructor's Initials _ Lab 12 137Explanation / Answer
1) Small amounts of HCl release less acidic vapors which are dangerous , if Hydrochloric acid
is not kept to minimum then it will release huge amount of vapors which can be fatal to
humans and corrosive to the surroundings.
2) a. Protecting eyes by using safety goggles, because the liquids might splash.
b. Using ring stand setup is safe
c. swirl the liquid gently over the hottest spot of the flame
d. Hold it at a certain angle and keep its mouth away from your face.
3) Na2CO3 (s) + 2 HCl (aq) ------> 2 NaCl (aq) + H2O (l) + CO2 (g)
4) NaHCO3 (s) + HCl (aq) ------> NaCl (aq) + H2O (l) + CO2 (g)
5) Molar mass of Na2CO3 = 105.9888 g/mol
moles of Na2CO3 = 0.73g / 105.9888g/mol = 6.8875*10-3 mol
6) Molar mass of NaHCO3 = 84.007 g/mol
moles of NaHCO3 = 0.65g / 84.007 g/mol = 7.7374*10-3 mol
7) P = 745.6 mmHg / 760 mmHg = 0.98105 atm ; n = 0.0083 mol
T = 20+273.15 = 293.15 K ; R = 0.0821 atm L mol-1K-1
Use PV = nRT equation to find V
V = 0.0083*0.0821*293.15 / 0.98105 = 0.20361 L
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