12/2/2017 11:55 PM 68.8/100 () 11/30/2017 08:03 PM Gradebo Print Calculator -d P

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12/2/2017 11:55 PM 68.8/100 () 11/30/2017 08:03 PM Gradebo Print Calculator -d Periodic Table Question 18 of 18 Map dt Organic Chemistry Loudon Roberts & Company Publishers presented by Sapling Learning Calculate the number of pounds of CO2 released into the atmosphere when a 18.0-gallon tank of gasoline is burned in an automobile engine. Assume that gasoline is primarily octane, CBH1B, and that the density of gasoline is 0.692 g mL-1 (this assumption ignores additives). Also assume complete combustion. Useful conversion factors: Number 1 gallon = 3.785 L 1 kg = 2.204 lb lb

Explanation / Answer

Volume of gasoline = 18 gallon

= 18 gallon x 3.785L/gallon

= 68.13 L

denisty of gasoline = 0.692g/mL

= 0.692 kg /L

and density = mass /volume

thus mass of gasoline = density x volume

= 0.692 Kg/L x 68.13 L

= 47.146 Kg

The balanced equation for combustion of gasoline is

C8H18 + 25/2 O2 --------------> 8CO2 + 9H2O

thus one mole of gasoline gives 8 moles of CO2

C8H18 + 25/2 O2 --------------> 8CO2 + 9H2O

1mol   8 x 44g of CO2

47.146x103 g/114g/mol

=4.135x102 mol gives 4.135x102 mol x8 x44g/mol of CO2

thus mass of CO2 = 145.573 kg

= 145.573 Kg x 2.204lb/Kg

= 320.84 lB of CO2

So 320.84 pounds of CO2 is released into atmosphere by burning 18 galon gasoline.

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