Name 1) Which of the following choices reprenents a Brensted-Lowry acid that is

Question

Name 1) Which of the following choices reprenents a Brensted-Lowry acid that is paired with its conjugate base? Acid HPO 1280 Conjugate Base Coll N1 O11 SO4 (aq) + HCO, (aq) The reaction represented above is observed to proceed spontaneously to the right in aqueous solution. Which of the following statement is true? 2) a. COs2 is the strongest base in this system because the value of K for the reaction is b. COs2 is the strongest base in this system because the value of K for the reaction is c. SO is the strongest base in this system because the value of K for the reaction is d. SO4 is the strongest base in this system because the value of K for the reaction is less than I1 greater than I less than 1 greater than I 3) Which of the following solutions has the highest pH? a. 0.1 M sodium nitrate, NaNO2 b. 0.1 M potassium bromide, KBr c. 0.1 M Lithium chlorate, LiCIO3 d. 0.1 M iron III nitrate, Fe(NO3)3

Explanation / Answer

Q1.

First, let us define Bronsted Lowry acid/base:

Bronsted Lowry acid: any species that will donate H+ (protons) in solution, and makes pH lower (i.e HCl)

Bronsted Lowry base: any species that will accept H+ (protons) in solution, and makes pH higher (NH3 will accept H+ to form NH4+)

Typically, acid/bases are shown in the left (reactants)

when we write the products:

Bronsted Lowery conjugate base = the base formed when the B.L. acid donates its H+ proton ( i.e. HCl -> Cl-

Bronsted Lowery conjugate acid = the acid formed when the B.L. base accept its H+ proton ( i.e. NH4+ has accept H+ proton)

Note that, typically conjugate bases/acids are shown in the right (product) side

So, from your reaction:

then

HSO4- = acid, CO3-2= base, SO4-3= conjguate base, HCO3- = conjguate acid

Q2.

a) true, since it accepts H+

b) False, mainly because of Kb

c) false, it is the weakest base

d) false, it is the weakest base

Q3

highest ph --> must be basic

form the list, only

NaNO2 hydrolysis to form

NO2- + H2O <- >HNO2+ OH-

therefore, choose A

Related Questions

Navigate

• Browse (All)
• Browse N
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.