A-pred compounds. If th ict whether a precipitation reaction will take place bet

Question

A-pred compounds. If th ict whether a precipitation reaction will take place between two aqueous solutions of ionic K2SO4(aq) +Pb(NO3 )2(aq) CaCh(aq) + Na,PO4(aq) L e answer is yes, write the complete equation for the reaction. Otherwise write NR. a) b) KNO3(aq) + Nigh(aq) d) Solutions of iron (Il) sulfate and barium hydroxide are mixed. e) Solutions of potassium chloride and silver nitrate are mixed Dichlorine monoxide, C120 is sometimes used as a powerful chlorinating agent in research. It can be produced by passing chlorine gas over heated mercury (I1) oxide according to the following equation: -6 What is the percent yield, if the quantity of the reactants is sufficient to produce 0.86g of Cl,O but only 0.71 g is obtained?

Explanation / Answer

a. K2SO4(aq) + Pb(NO3)2(aq) -------> PbSO4(s) + 2KNO3(aq)
      2K^+(aq)+SO4^2-(aq) + Pb^2+(aq) +2(NO3)^-(aq) -------> PbSO4(s) + 2K^+(aq)+2NO3^-(aq)
    removal fo spectator ions to get net ionic equation
SO4^2-(aq) + Pb^2+(aq) -------> PbSO4(s)
b. 3CaCl2(aq) + 2Na3PO4(aq) -----------> Ca3(PO4)2(s) + 6NaCl(aq)

   3Ca^2+ (aq) +6Cl^-(aq) + 6Na^+ (aq)+3PO4^3-(aq) -----------> Ca3(PO4)2(s) + 6Na^+ (aq) +6Cl^-(aq)
removal of spectator ions to get net ionic equation
3Ca^2+ (aq) +3PO4^3-(aq) -----------> Ca3(PO4)2(s)
c. 2KNO3(aq) + MgI2(aq) --------> 2KI(aq) + Mg(NO3)2(aq)

   2K^+ (aq) +2NO3^-(aq) + Mg^2+ (aq)+2I^-(aq) --------> 2K^+(aq)+2I^-(aq) + Mg^2+(aq)+2(NO3)^-(aq)
d. FeSo4(aq) + Ba(OH)2(aq) --------> Fe(OH)2(aq) + BaSo4(s)
   Fe^2+ (aq) +So4^2-(aq) + Ba^2+ (aq) +2(OH)^-(aq) --------> Fe^2+(aq)+2(OH)^-(aq) + BaSo4(s)
    removal of spectator ions to get net ionic equation
So4^2-(aq) + Ba^2+ (aq) --------> BaSo4(s)
e. KCl(aq) + AgNo3(aq) -----------> AgCl(s) + KNO3(aq)

   K^+ (aq) +Cl^-(aq) + Ag^+ (aq)+No3^-(aq) -----------> AgCl(s) + K^+ (aq) +NO3^-(aq)
   removal of spectator ions to get net ionic equation
Cl^-(aq) + Ag^+ (aq) -----------> AgCl(s)
6.percnetage yield = actual yield *100/theoriticcal yield
                    = 0.71*100/0.86   = 82.56% >>>>answer

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