-Test 4 | 5013 Sadia A chemical engineer is studying the two reactions shown in
ID: 591625 • Letter: #
Question
-Test 4 | 5013 Sadia A chemical engineer is studying the two reactions shown in the table below In each case, he fills a reaction vessel with Then, he measures the reaction enthalpy H and reaction entropy AS of the first reaction, and the reaction enthalpy H and reaction free energy AG of the some mixture of the reactants and products at a constant temperature of 90.0 "C and constant total pressure. second reaction. The results of his measurements are shown in the table. Complete the table. That is calculate G for the first reaction and AS for the second. (Round your answer to zero decimal places.) Then, decide whether under the conditions the engineer has set up, the reaction is spontaneous, the reverse reaction is spontaneous, or neither forward nor reverse reaction o this reaction 1005. Which is reaction 18Explanation / Answer
1)
deltaH = 70.0 KJ
deltaS = 239 J/K
= 0.239 KJ/K
T= 90.0 oC
= (90.0+273) K
= 363 K
we have below equation to be used:
deltaG = deltaH - T*deltaS
deltaG = 70.0 - 363.0 * 0.239
deltaG = -16.757 KJ
Answer: -17 KJ
since delta G is negative, this reaction is spontaneous
2)
deltaG = 25 KJ
deltaH = 1005 KJ
T= 90 oC
= (90+273) K
= 363 K
we have below equation to be used:
deltaG = deltaH - T*deltaS
25.0 = 1005.0 - 363.0 *deltaS
deltaS = 2.6997 KJ/K
deltaS = 2700 J/K
Answer: 2700 J/K
since delta G is positive, the reverse reaction is spontaneous
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