A 0.245 g sample of H2O(l) is sealed into an evacuated 3.30 L flask. What is the

Question

A 0.245 g sample of H2O(l) is sealed into an evacuated 3.30 L flask. What is the pressure (mmHg) of the vapor in the flask at the following temperatures?

Question 8 Part A A 0.245 g sample of H2O() is sealed into an evacuated 3.30 pressure of the vapor in the flask at the following temperatures? L flask. What is the 30.0 °C P 77.86 mm Hg Submit My Answers Give Up Incorrect: Try Again; 4 attempts remaining Part B 50.0 °C mm Hg Submit My Answers Give Up Part C 70.0 °C mm Hg Submit My Answers Give Up

Explanation / Answer

no of moles of H2O   = W/G.M.Wt

                                  = 0.245/18 = 0.0136 moles

n = 0.0136moles

V = 3.3L

T = 30+273   = 303K

R = 62.36mmHg/mole-K

PV = nRT

P   = nRT/V

     = 0.0136*62.36*303/3.3   = 77.87mmHg

part-B

n = 0.0136moles

V = 3.3L

T = 50+273   = 323K

R = 62.36mmHg/mole-K

PV = nRT

P   = nRT/V

     = 0.0136*62.36*323/3.3   = 83mmHg

part-C

n = 0.0136moles

V = 3.3L

T = 70+273   = 343K

R = 62.36mmHg/mole-K

PV = nRT

P   = nRT/V

     = 0.0136*62.36*343/3.3   = 88.15mmHg

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