° Half-Reaction E ° (V) F 2 (g) + 2e 2F (aq) 2.866 Co 3+ (aq) + e Co 2+ (aq) 1.9
ID: 591295 • Letter: #
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°
Half-Reaction E°
(V) F2 (g) + 2e 2F (aq) 2.866 Co3+ (aq) + e Co2+ (aq) 1.92 H2O2 (aq) + 2H+ (aq) + 2e 2H2O (l) 1.776 Au+ (aq) + e Au (s) 1.692 MnO4 (aq) + 8H+ (aq) + 5e Mn2+ (aq) + 4H2O (l) 1.507 Au3+ (aq) + 3e Au (s) 1.498 Cl2 (g) + 2e 2Cl (aq) 1.35827 O2 (g) + 4H+ (aq) + 4e 2H2O (l) 1.229 MnO2 (s) + 4H+ (aq) + 2e Mn2+ (aq) + 2H2O (l) 1.224 2IO3 (aq) + 12H+ (aq) + 10e I2 (s) + 6H2O (l) 1.195 Br2 (l) + 2e 2Br (aq) 1.066 VO2+ (aq) + 2H+ (aq) + e VO2+ (aq) + H2O (l) 0.991 HNO2 (aq) + H+ (aq) + e NO (g) + H2O (l) 0.983 NO3 (aq) + 4H+ (aq) + 3e NO (g) + 2H2O (l) 0.957 Ag+ (aq) + e Ag (s) 0.7996 Fe3+ (aq) + e Fe2+ (aq) 0.771 O2 (g) + 2H+ (aq) + 2e H2O2 (aq) 0.695 MnO4 (aq) + 2H2O (l) + 3e MnO2 (s) + 4OH (aq) 0.595 I2 (s) + 2e 2I (aq) 0.5355 Cu+ (aq) + e Cu (s) 0.521 O2 (g) + 2H2O (l) + 4e 4OH (aq) 0.401 Cu2+ (aq) + 2e Cu (s) 0.3419 HSO4 (aq) + 3H+ (aq) + 2e H2SO3 (aq) + H2O (l) 0.172 Cu2+ (aq) + e Cu+ (aq) 0.153 Sn4+ (aq) + 2e Sn2+ (aq) 0.151 2H+ (aq) + 2e H2 (g) 0.000 Fe3+ (aq) + 3e Fe (s) 0.037 Pb2+ (aq) + 2e Pb (s) 0.1262 CrO42 (aq) + 4H2O (l) + 3e Cr(OH)3 (s) + 5OH (aq) 0.13 Sn2+ (aq) + 2e Sn (s) 0.1375 Ni2+ (aq) + 2e Ni (s) 0.257 Co2+ (aq) + 2e Co (s) 0.28 PbSO4 (s) + H+ (aq) + 2e Pb (s) + HSO4 (aq) 0.3588 Cr3+ (aq) + e Cr2+ (aq) 0.407 Fe2+ (aq) + 2e Fe (s) 0.447 Cr3+ (aq) + 3e Cr (s) 0.744 Zn2+ (aq) + 2e Zn (s) 0.7618 2H2O (l) + 2e H2 (g) + 2OH (aq) 0.8277 Cr2+ (aq) + 2e Cr (s) 0.913 N2 (g) + 4H2O (l) + 4e 4OH (aq) + N2H4 (aq) 1.16 Mn2+ (aq) + 2e Mn (s) 1.185 Al3+ (aq) + 3e Al (s) 1.676 Sc3+ (aq) + 3e Sc (s) 2.077 Mg2+ (aq) + 2e Mg (s) 2.372 Na+ (aq) + e Na (s) 2.71 Ca2+ (aq) + 2e Ca (s) 2.868 Ba2+ (aq) + 2e Ba (s) 2.912 Using standard reduction potentials from the ALEKS Data tab, calculate the standard reaction free energy AG for the following redox reaction. Round your answer to 3 significant digits 10Cl_ (aq) + 210, (aq) + 12H+ (aq) 5Cl2 (g) +1, (s) + 6H,0 (1) kJ ×1Explanation / Answer
Cl2 (g) + 2e 2Cl (aq) ,Eo(=1.35827
So,2Cl (aq) --->Cl2 (g) + 2e Eo=-1.35827V [oxidation half reaction] }*5
2IO3 (aq) + 12H+ (aq) + 10e I2 (s) + 6H2O (l) Eo=1.195 [reduction half rection]
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net reaction: 10Cl (aq) +2IO3 (aq) + 12H+ (aq) --->5 Cl2 (g) +I2 (s) + 6H2O (l)
Eo(cell)=Eo(red)+Eo(oxidation)=1.195V+(-1.35827)=-0.16327V
delta Go=standard free energy change=-nF Eo(cell)
where n=net mol of electrons exchanged in the redox reaction
F=faraday's constant =96485C/mol
delta Go=-(10 mol e)*96485C/mol*(-0.16327J/C)=-157531.059 J=157531.059J*(1KJ/1000J)=157.531KJ
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