SIncorrect presented by Sapling Leaming Mapdb Using the following data, Compound
ID: 591216 • Letter: S
Question
SIncorrect presented by Sapling Leaming Mapdb Using the following data, Compound | Melting point (C) |us (kJ/mol) | Bolling point () | Arp (kJimd) HF HCI -114.3 HBr Hi 83.11 -86.96 -50.91 4.577 1.991 2.406 2.871 19.54 -84.9 -67.0 35.38 25.18 17.53 19 27 21.16 calculate AStus nd ASvpfor Hi. Number Number As 12.9271 J/(K mol Determine the entropy change when 4.30 mol of Hil(g) condenses at atmospheric pressure incorrect The value of AS. above is tor t.00 mol of Number [38291 ] J/K/ HYou need to scale that value up for 4.30 mol of H Also, consider the sign of your answer Does condensing resut in an increase or decrease entropy? Try AganNe Et- °Previous Give Up & View SolutionExplanation / Answer
for 1 mol HI ----------------> delta Svap = 89.0497 J/K .mol
for 4.30 mol HI -------------> ??
delta S = 4.30 x 89.0497
= 382.91 J/K
here entropy is decreases. so consider negative sign
delta S = - 382.91 J/K
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