.oooo AT&T; 5:40 PM c 64 %. www-awh.aleks.com Designing a galvanicc A chemist de

Question

.oooo AT&T; 5:40 PM c 64 %. www-awh.aleks.com Designing a galvanicc A chemist designs a galvanic cell that uses these two half-reactions red = +1.00 V Cl2(g)+ 2e- 2C1-(aq) +1.359 v Answer the following questions about this cell Write a balanced happens at the Write a balanced equation for the happens at the equation for overall reaction that powers the cell. Be sure the reaction s Do you have Yes enough calculate the ce voltage under If you said it was possible to caloulate the cell voltage, do so enter your answerv Round your significant digits Check

Explanation / Answer

Solution:- (1) From the given standard reduction potentials, the potenstial is less for the first half equation it means that's anode and the second half is cathode.

So, cathode half equation is..

Cl2(g) + 2e- -----> 2Cl-(aq) E0 = 1.359 V

(2) Anode half equation would be..

2NO(g) + 2H2O(l) -----> 2HNO2(aq) + 2H+(aq) + 2e- E0 = -1.00 V

(3) The over all equation means adding the two half equations...

Cl2(g) + 2NO(g) + 2H2O(l) -----> 2Cl-(aq) + 2HNO2(aq) + 2H+(aq)

(4) Yes, we have the enough information to calculate the cell voltage under standard conditions.

(5) E0(cell) = E0(reduction) + E0(oxidation)

E0(cell) = 1.359 V +(-1.00 V) = 0.359 V

for two significant digits it would be 0.36 V.

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