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(a) One cycle of Edman degradation of intact FI yields 2 mol of PTH-aspartate pe

ID: 59078 • Letter: #

Question

(a) One cycle of Edman degradation of intact FI yields 2 mol of PTH-aspartate per mole of FI. (b) Treatment with ?-mercaptoethanol yields two pentapeptides. (c) Treatment of FI with trypsin in the presence of ?-mercaptoethanol yields three peptides with the following composition: (Ala,Cys,Phe), (Arg,Asp), and (Asp,Cys,Gly,Met,Phe). The intact (Ala,Cys,Phe) peptide yields PTH-cysteine in the first cycle of Edman degradation. (d) Treatment of 1 mol of the intact FI with carboxypeptidase yields 2 mol of phenylalanine. (e) Treatment of the intact pentapeptide (Asp,Cys,Gly,Met,Phe) with CNBr yields two peptides, a dimer and a trimer. The tripeptide yields PTH-glycine in the first round of Edman degradation.

Explanation / Answer

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