LIVE Prct of the Rollowing maction froes a vicinal dibeomide f141 which orthe fo

Question

LIVE Prct of the Rollowing maction froes a vicinal dibeomide f141 which orthe follow.ng magents can be-.omparean ally.- IIS). Which talement is true about the rewult is oxymercuration-reduction neaction (D) Anti-Markevnikow addition of l (E) mone of the above 16) Product in the reaction ef4gte with excess Bn in CCL (C) 2,2-dibeomo butane 2-dichlono butane (D) 1,12-tetrabromo butane (B) 1.2-dibroeno butane (E) 1 -bromo, 2-chlono butane t7 Now many disinct intermal alkyses exist with formuls of CaHio (A)I (B)2 (C)3 (D)4 (E)s [I8J. Enol intermediates are formed in the reaction (A) alkene hydrogenation with H/Pd (B) alkene reaction with H:0-acid (C) Be adfision to alloynes (D) per acid oxidation of alkenes (E) Hydroboration-oxidation of allkynes ml CH(icling citans) 7 (A)2 (B) 3 (C4 (D)5 (21J Which of the following carbonium ion is likely to rearrange ? (22J. Which of the following reagent(s) gives trans-1.2-dichlorocyclohexane from cyclohexene ? [23]. Which of the following reageni(s) gives the reaction: aximothy 2-butene- (A) KMnO/ ag. H (B)0s0,/ NaliSO, (O0/HH (D) O,, then Zn/aq, acid (E) OJ HC (241 IUPAC name of the following compound H (A) 4-heptyn-2-ol (B)4-heptan-2ol (D) (25). (C) 3-beptyn-6-ol (D) 4-beptene-2-ol (E) 3-heptyn-2-ol Which of the following reagents (a, b) gives the reactions below (C)a- NaNH, then CHl, b Na/Liq NH (E) a NaNH, then CH.L, b-H/Lindlar catalyst (B) a- NaNH, then CHjl, b H/P (D) a- NaNH, then CH,OH, b-Hy/Lindlar catalyst

Explanation / Answer

13) option E is correct

Explanation: NaNH2 is a strong base which abstracts acidic proton and produces acetylide anion which on further reaction with alkyl halide produces an extended carbon chain. H2, Pt reduces alkyne to alkane.

14) option B is correct

Explanation:KOH is a strong base and gives dehydrohalogenation and produces alkyne as product.

15) option A is correct

Explanation: The negative part of the reagent is added to the carbon atom having less number of hydrogens. In oxymercuration - demercuration, more substituted alcohol is formed as product.

16) option D is correct

Explanation: Br2 is added to alkyne and forms tetra bromo compound as product. Addition of Br2 is an anti addition.

17) option A is correct

Explanation: double bond equivalence = [2+2(C)-H]/2 = [2+2(6)-10]/2 = [14-10]/2 = 4/2 = 2.Therefore,it contains one triple bond.

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