s For the weak acld and weak base bekw that you titrated, the equilibrium reacti
ID: 590499 • Letter: S
Question
s For the weak acld and weak base bekw that you titrated, the equilibrium reactions and expressions ure The above two equations can be re-arranged to From the plot of the titration curve, the volume of titrant required to reach the en the volume of titrant added is exactly half of that volume, then dpoint can be read. When ) related to plH measured in the solution when the volume of titrant added is exactly half of that required to reach the equivalence point? he b). From the titration curves for acetic acid and ammonia, find the plH of each so concentration of the titrant is half of that required to reach the end po pH of the acetic acid solution pH of the ammonia solution how you solved for your a veosul s what do you predict the Ki of acetic acid and the Ki of ammonia are? (Show nswer below.)Explanation / Answer
a) When the volume of the titrant added is exactly half of that required to reach the end point of the titration, we have the equality relations as given.
Consider acetic acid; we have [H3C2O2- (aq)] = [H3C2OH (aq)]; plug this into the Henderson-Hasslebach equation and get
pH = pKa + log [H3C2O2- (aq)]/[H3C2OH (aq)]
====> pH = pKa + log (1) (the terms in square braces are equal)
====> pH = pKa (ans).
The same thing will hold for NH3. Exactly half way to the end point, we have [NH3 (aq)] = [NH4+ (aq)]. Plug this into the Henderson-Hasslebach equation for bases and obtain
pOH = pKb + log [NH4+ (aq)]/[NH3 (aq)]
====> pOH = pKb + log (1)
====> pOH = pKb (ans).
b) I need the titration curves.
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