JUST PART B A gas mixture contains each of the following gases at the indicated
ID: 590399 • Letter: J
Question
JUST PART B
A gas mixture contains each of the following gases at the indicated partial pressures: N2, 206 torr ; O2, 131 torr ; and He, 110 torr .
Part A
What is the total pressure of the mixture?
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Significant Figures Feedback: Your answer 446 torrwas either rounded differently or used a different number of significant figures than required for this part.
Part B
What mass of each gas is present in a 1.00 L sample of this mixture at 25.0 C?
Enter your answers numerically separated by commas.
A gas mixture contains each of the following gases at the indicated partial pressures: N2, 206 torr ; O2, 131 torr ; and He, 110 torr .
Part A
What is the total pressure of the mixture?
P = 447 torrSubmitMy AnswersGive Up
Correct
Significant Figures Feedback: Your answer 446 torrwas either rounded differently or used a different number of significant figures than required for this part.
Part B
What mass of each gas is present in a 1.00 L sample of this mixture at 25.0 C?
Enter your answers numerically separated by commas.
Explanation / Answer
A gas mixture contains each of the following gases at the indicated partial pressures: N2, 206 torr ; O2, 131 torr ; and He, 110 torr .
total pressure = sum of partial pressure of individual gases =206+131+110 Torr=447 Torr
Mole fraction = moles of gas/total moles of gas
but from gas law, PV=nRT, moles of gas =partial pressure of gas* V/RT
since partial pressure is defined as the pressure exereted if the gas alone occupies the entire volume,
total moles= total pressure of gas*V/RT
hence moles of gas/total moles = mole fraction = partial pressure of gas/total pressure
mole fractions : N2=206/447=0.46, O2= 131/447= 0.29 and He= 110/447= 0.25
total moles of gas can be calculated from n, =PV/RT
P= total pressure in atm= 447/760 atm (760 torr =1atm)=0.59, V= 1L, T= 25deg.c= 25+273= 298K, R= gas constant =0.0821 L.atm/mole.K, n= 0.59*1/(0.0821*298)= 0.024 mole
but mole fraction = moles of gas /total moles
moles of gas =mole fraction* total moles
moles of gases : N2= 0.46*0.024=0.011, O2= 0.29*0.024=0.007 and He= 0.024*0.25=0.006
moles = mass/molar mass, mass =molar mass* moles, molar masses (g/mole): N2= 28, O2=32 and He =40
masses : N2=0.011*28 gm =0.308 gm, O2=0.007*32 =0.224 gm and He=0.006*40 = 0.24 gm
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