Enter your answer in the provided box. What is the standard emt of a galvanic ce

Question

Enter your answer in the provided box. What is the standard emt of a galvanic cell made of a Pb electrode in a 1.0 M Pb(NOs)2 solution and a Cr electrode in a 1.0 M Cr(NO3)3 solution at 25°C? 0 cell Standard Reduction Potentials at 25 C Half-Reaction EV +2.87 +2.07 +1.82 0s(g) + 2H+(aq) + 2e-_02(g) + H2O Cu (ag) + 2e Cus) AgCl(s) + e.. Ag(s) + Cl-(aq) so2-(ap + 4H+(aq) + 2e-_ SO2(g) + 2H20 +0.34 +0.22 +0.20 +0.15 +0.13 0.00 -0.13 -0.14 -0.25 -0.28 -0.31 -0.40 -0.44 -0.74 -0.76 -0.83 Pb (aq) + ePbs) Sn (aq) + 2eSns) Ni2+ (aq) + 2e No Co2+(aq) + 2e + Co(s) Cd2+(aq) + 2e Cd(s) Fe (a) + 2eFes) Cr (aq) + 3eCr(s) Zn2+(aq) + 2e- Zn(s) Mn (ag) + 2eMns) AP"(aq) + 3e"- Al(s)

Explanation / Answer

from data table:

Eo(Cr3+/Cr(s)) = -0.74 V

Eo(Pb2+/Pb(s)) = -0.13 V

the electrode with the greater Eo value will be reduced and it will be cathode

here:

cathode is (Pb2+/Pb(s))

anode is (Cr3+/Cr(s))

The chemical reaction taking place is

3 Pb2+(aq) + 2 Cr(s) --> 3 Pb(s) + 2 Cr3+(aq)

Eocell = Eocathode - Eoanode

= (-0.13) - (-0.74)

= 0.61 V

Answer: 0.61 V

Feel free to comment below if you have any doubts or if this answer do not work. I will edit it if you let me know

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