A hydrocarbon with the chemical formula C2H2 reacts with oxygen to produce carbo

Question

A hydrocarbon with the chemical formula C2H2 reacts with oxygen to produce carbon dioxide and water vapor 2 C2H2(g) + 5 O2(g) 4 CO2(g) + 2 H2O(g) A. If you mix C2H2 and O2 in the correct stoichiometric ratio, and if the total pressure of the mxture is 420. mm Hg, what are the partial pressures of the gases before the reaction occurs? partial pressure of C2H2- mm Hg partial pressure of O2 = mm Hg B. What are the partial pressures of the product gases after the reaction has completed? mm Hg partial pressure of CO2 partial pressure of H2O . Some Possibly Useful Information mm Hg IR·00821 met K . 8 314 more mol-K = 8.3 14-1 mol K

Explanation / Answer

stoichiometric ratios : 2:5

so that,

molefraction of C2H2 = 2/7 = 0.286

molefraction of o2 = 5/7 = 0.714

Partial pressure of C2H2 = xC2H2*pTotal

                           = 0.286*420 = 120.12 mmhg

Partial pressure of O2 = xO2*pTotal

           = 0.714*420 = 299.88 mmHg

B. after the reaction only products are present

    P1/n1 = P2/n2

    420/7 = P2/6

P2 = final pressure = 360 mmhg

stoichiometric ratios products :4:2

molefraction of Co2 = 4/6 = 0.67

molefraction of H2O = 2/6 = 0.33

Partial pressure of CO2 = xCO2*pTotal

                           = 0.67*360 = 241.2 mmhg

Partial pressure of H2O = xH2O*pTotal

                          = 0.33*360

                          = 118.8 mmhg

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