Enthalpy of solution for the dissolution of a salt. Can somebody help me with th
ID: 589034 • Letter: E
Question
Enthalpy of solution for the dissolution of a salt. Can somebody help me with these ? Thank youC. - Enthalpy (Heat) of Solution for the Dissolution of a Salt. Name of Salt: Ammonium Chloride 1.- Mass of salt (g) 2.- Moles of salt (mol) 3.- Mass of calorimeter (g) 4. Mass of calorimeter+ water (g) 5- Mass of water (g) 6. Initial temperature of water(C) 7.- Final temperature of mixture from graph (C) 8.- Instructor's approval of graplh 50g 0.93 mol 3.78 23.38 19.6g 24.7 23.3 C Calculations for Enthalpy (Heat) of Solution for the Dissolution of a Salt. 1- Temperature change of solution AT (T) 2.- Heat change of water (J) Q = m·C-AT 3.- Heat change of salt (J) (Obtain its specific heat from table 25.1) 4.- Total enthalpy change 5 AHs (J/mol salt), equation 25.12 6.- Average H8 (J/mol salt) 140 1.57J/g C
Explanation / Answer
heat change of water =mass of water* specific heat of water* change in temperature = -19.6*4.184*1.4=-114.81 Joules
heat change of salt also= mass of salt* specific heat of salt* change in temperature =- 5*1.57*1.4=-31.4 joules
total heat change=-114.81-31.4 =-146.21 joules
this is the enthalpy change when 0.93 moles of salt is used.
hence enthalpy change/mole of salt= -146.21/0.93 joules/mole=-157 j/mole= -0.157 Kj/mole
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.