used in biomedical research for which 2. [1 points]. Caenorhabditis elegans (the
ID: 588827 • Letter: U
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used in biomedical research for which 2. [1 points]. Caenorhabditis elegans (the famous model organism 3 Nobel prizes have been awarded) has 5 autosomes and an X chromosome. Hermaphrodites have two X chromosomes (XX) and males have only one (that is, males are XO, where the "O" stands for 'no homolog for the X', or "nullo"). Draw mitosis the total number of possible combinations of chromosomes in Celegans male sperm due to independent assortment at Metaphase lof melosis? Another way to think about the question is, disregarding recombination/crossing-over, what is the total number of genetically diferent male gametes produced a male and for a hermaphrodite. What is nat is the total number of genetically gametes produced g that homologous pairs are different in at least one locus?] [Hint: Males can produce gametes that are "nullo" (O) for the X as well as gametes that have an X, because the X dyad only segregate one of the two poles during meiosis I.] Explain your answer.Explanation / Answer
There is the following four types of male gametes would form:
AAA +X, AA+X, AAA+0, AA+0
This is because C. elegans has 5 autosomes which will divide in frame of AAA and AA. Now males has one X chromosome so it will taken by two cells having AAA and AA to form AAA +X, AA+X; which are required for female production. And other gametes will no sex chromosome and have combination of AAA+0, AA+0; this is required for male production.
If 1 allele locus difference in homologous pair then the following genetically different gametes will occur
The four chromosome gamete AAA +X has possibility of combination 4! = 4x3x2x1 = 24
The three chromosome gametes AA+X and AAA+0 have possibility of combination (3! For each) x2 = (3x2x1) x 2 = 12
The two chromosome gamete AA+0 has possibility of combination 2! = 2x1 = 2
So total genetically different gametes will occur = 24+12+2 = 38
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