19. Calculate the de Broglie wavelength of a 1.90x10 kg bullet traveling at 700

Question

19. Calculate the de Broglie wavelength of a 1.90x10 kg bullet traveling at 700 miles per hour (313 m/s). 20. The following is a diagram of energy states and transitions in the hydrogen atom n : Infinity n.3 ENERGY Match each of the responses below with the correct arrow from the figure. The emission line with the shortest wavelength a. b. c. d. e· f. The absorption line with the shortest wavelength The emission line with the highest energy The absorption line with the highest energy The emission line with the highest frequency The line corresponding to the ionization energy of hydrogen. 21. In the Bohr model of the hydrogen atom, the electron occupies distinct states. One transition between energy states of the hydrogen atom is represented by the picture below n- 3 a. b. c. In this transition an electron moves the n·-level to the n =-level. Is energy absorbed or emitted by this process? Does the electron move closer to or further from the nucleus in this process? 22. The following is a diagram of energy states and transitions in the hydrogen atom infinity n 4 n-3 ENERGY Match each of the responses below with the correct arrow from the figure a. The emission line with the shortest wavelength. b. The absorption line with the longest wavelength c. The emission line with the highest energy d. The absorption line with the lowest energy e. The emission line with the lowest frequency.

Explanation / Answer

19)

so, we have:

v = 3.13*10^2 m/s

mass, m = 1.9*10^-3 Kg

we have below equation to be used:

wavelength = Planck constant / (mass*velocity)

wavelength = (6.626*10^-34) / (1.9*10^-3*3.13*10^2)

wavelength = 1.11*10^-33 m

Answer: 1.11*10^-33 m

Feel free to comment below if you have any doubts or if this answer do not work. I will edit it if you let me know

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