Please answer 4, 5, & 6. Show work typed of written nice. No cursive writings. 4

Question

Please answer 4, 5, & 6. Show work typed of written nice. No cursive writings.

4. If the temperature of 50.25 grams of liquid water is raised from 23.0 to 27.5 deg. C, what is the At of the water? In the same experiment (#4 above), calculate the total heat flow (q) from the temperature change of the water. 5. e dumping of If the temperature change (of the water) in problem #4 above was caused by th 7.0 grams of hot copper metal, at an original temperature of 95.0 deg. C, what is the specific heat capacity of the copper in joules/gram deg. C of material? 6.

Explanation / Answer

4)
delta T = final T - initial T
= 27.5 - 23.0
= 4.5 oC
Answer: 4.5 oC

5)
we have:
m = 50.25 g
C = 4.184 J/g.oC
deltaT = 4.5 oC
we have below equation to be used:
Q = m*C*deltaT
Q = 50.25*4.184*4.5
Q = 946 J
Answer: 946 J

6)
we have:
Q = 946 J
m = 7 g
Ti = 27.5 oC
Tf = 95 oC
we have below equation to be used:
Q = m*C*(Tf-Ti)
946.0 = 7.0*C*(95.0-27.5)
C = 2.00 J/g.oC
Answer: 2.00 J/g.oC

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