Lab Day Mon. Tues. Thurs. Predict the products of each reaction pair below and w

Question

Lab Day Mon. Tues. Thurs. Predict the products of each reaction pair below and write a balanced equation. If a reaction will occur, wrte the net ionic equation as well. If no reaction occurs, write NO REACTION. (NIE ionic equation). You may wish to consult the rules for solubility on page 179 or in your lecture net notes 1) AgNO3 (aq) HCI (aq) AgCl() + HN03 (at) + 2)2 AgNO (aq) NaCOs (aq) NaNO, (aq) AgNO3 (aq) NIE 3) No Reaction + A12-S04+2NaNo3 4)|AgNO3 (aq) Naso, (aq) + NIE Aat 5) AgNOs (aq)Ba(NO,)2 NIE 6) HCI (aq) Na COs (aq) NIE 7) HCI (aq) NaNO, (aq)> NIE

Explanation / Answer

5) The anion is the same in both the salts; moreover, all NO3- salts are soluble in water. Hence there is no reaction.

6) 2 HCl (aq) + Na2CO3 (aq) --------> 2 NaCl (aq) + CO2 (g) + H2O (l)

Decompose the aqueous species into ions and get the total molecular equation.

2 H+ (aq) + 2 Cl- (aq) + 2 Na+ (aq) + CO32- (aq) --------> 2 Na+ (aq) + 2 Cl- (aq) + CO2 (g) + H2O (l)

Cancel out the common ions from both sides to get the NIE.

NIE: 2 H+ (aq) + CO32- (aq) --------> CO2 (g) + H2O (l)

7) HCl (aq) + NaNO3 (aq) --------> No Reaction

There may be a double displacement reaction producing NaCl and HNO3, but both being electrolytes will decompose into the respective ions and hence, there is no overall reaction.

8) HCl (aq) + Na2SO4 (aq) ----------> No Reaction

There may be a double displacement reaction producing NaCl and H2SO4, but both being electrolytes will decompose into the respective ions and hence, there is no overall reaction.

9) HCl (aq) + Ba(NO3)2 (aq) ----------> No Reaction

There may be a double displacement reaction producing BaCl2 and HNO3, but both being electrolytes will decompose into the respective ions and hence, there is no overall reaction.

10) Na2CO3 (aq) + NaNO3 (aq) --------> No Reaction

We have the same cation and hence, no displacement reaction is possible.

11) Na2CO3 (aq) + Na2SO4 (aq) ---------> No Reaction

We have the same cation and hence, no displacement reaction is possible.

12) Na2CO3 (aq) + Ba(NO3)2 (aq) ---------> BaCO3 (s) + 2 NaNO3 (aq)

Decompose the aqueous species into ions to get the total molecular equation.

2 Na+ (aq) + CO32- (aq) + Ba2+ (aq) + 2 NO3- (aq) ----------> BaCO3 (s) + 2 Na+ (aq) + 2 NO3- (aq)

Cancel the common ions from both sides to get the NIE.

NIE: CO32- (aq) + Ba2+ (aq) ---------> BaCO3 (s)

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