End of Chapter, Problem 12 The [R.L] [RT ratio gives the fraction of receptors t
ID: 588053 • Letter: E
Question
End of Chapter, Problem 12 The [R.L] [RT ratio gives the fraction of receptors that have bound ligand. Use the expression below, calculate the [R L] [RIT ratio under the following conditions. Calculate the [R·L] : [R]T ratio when Ka-5[L]. Express your answer using 2 significant figures. the tolerance is +/-296 Calculate the [R-L] : [Rlr ratio when Kd = [L]. Express your answer using 2 significant figures. the tolerance is +/-2% Calculate the [R-L] : [Rlr ratio when 5Kd = [L]. Express your answer using 2 significant figures. the tolerance is +/-2%Explanation / Answer
a) Given Kd = 5[L]; therefore,
[R.L] = [R]T[L]/(Kd + [L]) = [R]T[L]/(5[L] + [L]) = [R]T[L]/6[L] = [R]T/6
Now, [R.L]:[R]T = [R]T/6:[R]T = 1/6:1 = 1:6 (ans, multiplying both sides of the ratio by 6)
b) Given Kd = [L]; therefore,
[R.L] = [R]T[L]/(Kd + [L]) = [R]T[L]/([L] + [L]) = [R]T[L]/2[L] = [R]T/2
Now, [R.L]:[R]T = [R]T/2:[R]T = 1/2:1 = 1:2 (ans, multiplying both sides of the ratio by 2)
c) Given 5Kd = [L]; therefore, Kd = [L]/5
[R.L] = [R]T[L]/(Kd + [L]) = [R]T[L]/([L]/5 + [L]) = 5[R]T[L]/6[L] = 5[R]T/6
Now, [R.L]:[R]T = 5[R]T/6:[R]T = 5/6:1 = 5:6 (ans, multiplying both sides of the ratio by 6)
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