From a cross of RrYy x RrYy what is the probability of getting each of the follo
ID: 58793 • Letter: F
Question
From a cross of RrYy x RrYy what is the probability of getting each of the following genotypes?
A. RRYY B. rryy C. RrYy D. Rryy E. rrYY F. RrYY
a. 1/16; b. 2/16; c. 4/16; d. 2/16; e. 2/16; f. 2/16
a. 2/16; b. 4/16; c. 1/16; d. 2/16; e. 2/16; f. 1/16
a. 1/16; b. 4/16; c. 2/16; d. 1/16; e. 1/16; f. 2/16
a. 2/16; b. 2/16; c. 2/16; d. 2/16; e. 2/16; f. 2/16
a. 1/16; b. 1/16; c. 4/16; d. 2/16; e. 1/16; f. 2/16
A.a. 1/16; b. 2/16; c. 4/16; d. 2/16; e. 2/16; f. 2/16
B.a. 2/16; b. 4/16; c. 1/16; d. 2/16; e. 2/16; f. 1/16
C.a. 1/16; b. 4/16; c. 2/16; d. 1/16; e. 1/16; f. 2/16
D.a. 2/16; b. 2/16; c. 2/16; d. 2/16; e. 2/16; f. 2/16
E.a. 1/16; b. 1/16; c. 4/16; d. 2/16; e. 1/16; f. 2/16
Explanation / Answer
E. a. 1/16; b. 1/16; c. 4/16; d. 2/16; e. 1/16; f. 2/16
Cross between RrYy and RrYy will have the offspring with the following genotypes. The gametes produced are, RY, Ry, rY and yy.
RrYy* RrYy = RRYY (1/16), rryy (1/16) , RrYy (4/16), Rryy (2/16), rrYY (1/16), RrYY (2/16)
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