Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Multiple choice: (2 pts each) 7. In deciding which of two acids is stronger, one

ID: 587915 • Letter: M

Question

Multiple choice: (2 pts each) 7. In deciding which of two acids is stronger, one must know: a. the concentration of each acid solution. b. the pH of each acid solution c. the equilibrium constant of each acid. d. all of the above. Which of the following solutions contains the strongest acid? a. 5.00 M HCN (K.-6.2 x 10-) b. 3.50 M H CoHeOs (K-7.9x 10-, K c. 2.50 M HCHO, (k,-1.8 × 10-5) d. 4.00 M HOCI (K. = 3.5 x 10") e, 1.0 M HF (K, 7.2 x 10") 8. 1.6x 10). 9. Which of the following is true for a buffered solution a. The solution resists change in its [H'] b. The solution will not change its pH very much even if a concentrated acid is added. c. The solution will not change its pH very much even if a strong base is added. d. All of these. 10. The pH at the equivalence point of a titration of a weak acid with a strong base will be a. less than 7.00 b. equal to 7.00 c. greater than 7.00 d. equal to the pk, of the acid e. more data needed to answer this question 11. Methyl orange is an indicator with a K, of 1 × 10". Its acid form, Hin, is red, while its base form, In", is yellow. At pH 6.0, the indicator will be a. red b. orange c. yellow d. blue e. not enough information 12. If 25.0 ml of 0.451 M NaOH solution is titrated with 0.253 M H,so, the flask at the endpoint will contain (besides the indicator phenolphthalein) as the principal components: a. sodium hydroxide, sulfuric acid, and water b. dissolved sodium sulfate and water c. sodium hydroxide, sodium sulfate, and water d. dissolved sodium sulfate, sulfuric acid, and water

Explanation / Answer

7)

The one with higher equilibrium constant will be stronger acid

Answer: c

8)

Ka is highest for HF

So, this is strongest

Answer: e

9)

buffer resist the change in pH when small amount of acid or base is added

Answer: d

Only 1 question at a time please