4. Make sure the electronic thermometer is switched off. Data Tables: Part A: Ne

Question

4. Make sure the electronic thermometer is switched off. Data Tables: Part A: Neutralization of 1.00 M HCI with 1.00 M NaOH Trial 1 Trial 2 Total volume after mixing 1 Part B: Neutralization of 0.500 M HCI with 0.500 M NaOH Trial 1 Trial 2 Total volume after mixing 2°C AT Calculations (1.00 M HCI and Part B (0.500 M H 1.00 M NaOH) Part A and 0.500 M NaOH) Trial 2 Trial 1 Trial 2 AT at mixing Mass of calorimeter 3.59 333 33.433.3 empty Mass of calorimeter, full Mass of resulting solution Jetea1o Moles of HCI reacted Average molar AH Overall average molar Heeutralration Difference between two average molar AH Percent difference between two average molar AHnesdralization Enthalpy of Neutralization

Explanation / Answer

Solution:-

Ques. No-1

Exothermic type of thermochemical reaction was observed in this experiment. As during reaction heat is evolved.

sign of heat of neutralization is consistent with this ..i.e negative sign. As heat is generated from system.

Q = mcT = 100.85 g x 4.1814 J/(g x °C) x 7.2°C

= -3.036 kJ

this energy is for 50 ml 1M solution of HCl i.e 0.05 mole of HCl

Ques. No-2

50.0 mL of 0.250 M HCl contains 0.0125 moles of HCl.

Here, 0.05 mole of HCl gives energy on neutralization = 3.036kJ

1 mole of HCl gives energy on neutralization = 3.036 / 0.05 kJ

0.0125 mole of HCl gives energy on neutralization = 60.72 kJ * 0.0125

= 759 J

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