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e Economics question lCh x E Homepage ECON1B0. × -Bonus Pre Test Assignm x @Take a Test-Aashraya l /@Quizzes- HEMIE03 e x Secure https:/ avenue c mcnasier.ca d2 ms quizzing user/attempt quiz start ramed2l?ou=213383&isprv;=&drc;=0&q; 1692&c; =08 dnb-o avenue toleam CHEM 1E03:General Chemistry for Engineering 1 Aashraya Mehta 880 Content ResourcesCommunication Assessments PebblePad Quiz 6 st. Length: 166:39:00 Aashraya Mchta: Attempt 1 Question 9 (1 point) 0 of 10 questions saved Calculate Ka for an acid whose 0.30 M solution has a pH of 5.20 HA + H2O H3O+ + A Page 1: 6.3 x 106 1.3 x 10-10 4.0 x 10-11 7.5 x 10-5 none of the other options 4 6 Quiz Started O Type here to search 2017-11-25

Explanation / Answer

we have below equation to be used:

pH = -log [H+]

5.2 = -log [H+]

log [H+] = -5.2

[H+] = 10^(-5.2)

[H+] = 6.31*10^-6 M

Lets write the dissociation equation of HA

HA -----> H+ + A-

0.3 0 0

0.3-x x x

Ka = [H+][A-]/[HA]

Ka = x*x/(c-x)

Ka = 6.31*10^-6*6.31*10^-6/(0.3-6.31*10^-6)

Ka = 1.3*10^-10

Answer: 1.3*10^-10

Feel free to comment below if you have any doubts or if this answer do not work. I will edit it if you let me know

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