The equilibrium constant, K, of a certain first order reaction was measured at t

Question

The equilibrium constant, K, of a certain first order reaction was measured at two temperatures, T. The data is shown in this table.

Question 29 of 29 Map The equilibrium constant, K, of a certain first order reaction was measured at two temperatures, T. If you were going to graphically determine the enthalpy, AH, for this reaction, what points would you plot? The data is shown in this table Number Number To avoid rounding errors, use three significant figures in the x values and four significant figures in the y values point 1: T(K) K 225 825 5.49 3.00 Number Number point 2 Determine the rise, run, and slope of the line formed by these points rise run slope Number Number Number What is the standard enthalpy of this reaction? Number H = J/ mol

Explanation / Answer

We need to plot lnK on y axis and 1/T on x axis

K = 3.0

ln K = ln (3.0) = 1.09861

T = 225.0

1/T = 0.00444

point 1 is:

x = 0.00444

y = 1.09861

K = 5.49

ln K = ln (5.49) = 1.70293

T = 825.0

1/T = 0.00121

point 2 is:

x = 0.00121

y = 1.70293

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rise = (y1-y2) = 1.09861 - 1.70293 = -0.60432

rise = (X1-X2) = 0.00444 - 0.00121 = 0.00323

slope = rise/run

= -0.60432/0.00323

= -186.96025

----------------------------------------------------------------------------

use

slope = - delltaHo/R

= -186.96025 = -delltaHo/8.314

delltaHo = 1554.3875 J/mol

Answer: 1554 J/mol

Feel free to comment below if you have any doubts or if this answer do not work. I will edit it if you let me know

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