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Use this equation to answer the following questions: G = G RTZnQ Part H As a rea

ID: 587116 • Letter: U

Question

Use this equation to answer the following questions: G = G RTZnQ Part H As a reaction proceeds in the forward direction, the value of Q 1 Please Choose Submit My Answers Give Up Part l Therefore, the nonstandard value of G becomes Please Choose # Submit My Answers ive Up Part J A voltaic cell reaction becomes Please Choose as a reaction proceeds. Submit My Answers Give Up Part K-Recall: G = G.+ RTInQ Does the change in Q (you described in Parts G and H) cause the value of nonstandard G to become more positive or less positive than Go? (Remember that G should be negative for the spontaneous process.) the more positive G becomes. the less positive G becomes. The bigger the Q Submit My Answers Give Up For the following questions, refer to the relationship between nonstandard G and Ecell Part L For a working voltaic cell, a spontaneous reaction is occurring | The signs of G and Eell are ! Please Choose # , respectively. Submit My Answers Give Up Part M-What are the values of G and Eeell when the reaction in the cell has reached a state of equilibrium? AG and Ec are Please Choose Submit My Answers Give Up Part N-Consider how G changes as a reaction proceeds toward equilibrium (Parts I-K, above). larger negative value smaller negative value larger positive value smaller positive value The value of El becomes a as the reaction in the voltaic cell proceeds in the forward direction toward a state of equilibrium. Submit My Answers Give Up Part O-Recall: G =-nFEcell As the value of el becomes a smaller positive value, this results in a value of G and therefore a -spontaneous reaction. Please Choose

Explanation / Answer

H.

if forward, this is because there are much more reactants, than products, so

Q < 1, since products < reactants

I

nonstandard vlaue of dG must be very negative, since it is proceeding forward

J

the voltaic cell value must be decreasing, since Ecell decreases as reactants dissapear

K

as Q increases, then ln(Q) increases, then, RT*ln(Q) increases as well, so dG overall increases

L

spontaneous process

dg = negative

Ecell = positive

M

in equilbirium

dG = 0

and E cell = 0

N

as reaction goes towards equilbirium Ecell becomes nearest to 0, t becomes samller postivie valeu

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