A positively charged particle of mass 8e-8 kg is traveling due east with a speed

Question

A positively charged particle of mass 8e-8 kg is traveling due east with a speed of 75 m/s and enters a .29 t uniform magnetic field. The particle moves through one quarter of a circle in a time of 5.80e-3 s at which time it leaves the field heading due south. All during the motion the particle moves perpendicular to the magnetic field.
Determine the magnitude of the charge A positively charged particle of mass 8e-8 kg is traveling due east with a speed of 75 m/s and enters a .29 t uniform magnetic field. The particle moves through one quarter of a circle in a time of 5.80e-3 s at which time it leaves the field heading due south. All during the motion the particle moves perpendicular to the magnetic field.
Determine the magnitude of the charge
Determine the magnitude of the charge

Explanation / Answer

Force due to magnetic field = Centripetal force

qvB =mv2/r

since quarter of a circel

s=pir/2 =vt

=>r=2vt/pi

qB = pimv/2vt

=>q =pi*m/2*t*B =pi*(8*10-8)/2*(5.8*10-3)*0.29

q=7.47*10-5 C

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.