A doubly charged ion with velocity 5.80 x 10^6 m/s moves in a path of radius 36.

Question

A doubly charged ion with velocity 5.80 x 10^6 m/s moves in a path of radius 36.0 cm in a magnetic field of 0.75 T.m.a-mass spectrometer. What is the mass of this icon? Kg The drawing shows an end-view of two wires. They are long, straight, and perpendicular to the plane of the paper. Their cross sections lie at the comers of a 0.50-m square. The current in wire 1 is going into the page and it is equal to 12.0 A and the current in wire 2 is going out of the page and it is equal to 5.50 A respectively. What is the magnitude of the magnetic field at one of the empty corner? T A proton travels at a uniform speed of 2.90 x 10^6 m/s toward the left of this page. It then enters a uniform magnetic field and experiences a maximum force of 5.25 x 10^-8 N that points toward the top of the page. What is the magnitude of the magnetic field? T What is the directions of the magnetic field?

Explanation / Answer

q = 2 e = 2 * 1.6 x10-19

F = m v2 / r

B q v = m v2 / r

m = B q r/ v

= (0.75 * 2 * 1.6 x10-19 * 36 x10-2) / (5.8 x106)

= 1.49 * 10-26 Kg

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