Question Part Points Submissions Used A parallel-plate capacitor has capacitance

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Question Part
Points
Submissions Used

A parallel-plate capacitor has capacitance
C0 = 8.00 pF when there is air between the plates. The separation between the plates is 1.20 mm.
(a) What is the maximum magnitude of charge Q that can be placed on each plate if the electric field in the region between the plates is not to exceed 3.00 104 V/m?
C

(b) A dielectric with K = 2.60 is inserted between the plates of the capacitor, completely filling the volume between the plates. Now what is the maximum magnitude of charge on each plate if the electric field between the plates is not to exceed 3.00 104 V/m?
C

Question 2 different scenario

When a 430 nF air capacitor (1 nF = 10-9 F) is connected to a power supply, the energy stored in the capacitor is

(a) What is the potential difference between the capacitor plates?
V

(b) What is the dielectric constant of the slab?

Explanation / Answer

(A)
C0 = 8.00 pF
d = 1.20 * 10^-3 m
E = 3.0 * 10^4 V/m

E = /eo
= E* eo
Q/A = E* eo
Q = E* eo *A

Now,
C = A*eo/d
A = C*d/eo

Q = E* eo * C*d/eo
Q = E*C*d
Q = 3.0 * 10^4 * 8.0 * 10^-12 * 1.20 * 10^-3 C
Q = 2.88 * 10^-10 C

(B)
Now, K = 2.60
C =  K*A*eo/d

Q = E* eo * C*d/eo*K
Q = (E*C*d)/K
Q = (2.88 * 10^-10 *2.60)
Q = 7.488 * 10^-10 C
Please post seperate questions in seperate post

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