Two loudspeakers, 5.0 m apart and facing each other, play identical sounds of th

Question

Two loudspeakers, 5.0 m apart and facing each other, play identical sounds of the same frequency. You stand halfway between them, where there is a maximum of sound intensity. Moving from this point toward one of the speakers, you encounter a minimum of sound intensity when you have moved 0.25 m . Assume the speed of sound is 340 m/s. What is the frequency of the sound? Express your answer to two significant figures and include the appropriate units. If the frequency is then increased while you remain 0.25 m from the center, what is the first frequency for which that location will be a maximum of sound intensity? Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

Given speed of sound=340 m/s
(a) L1+L2= 5m

for minimum intensity

Ld=/2

Ld= |L1-L2|= (2.5+0.25)-(2.5-0.25)=0.50 m
Ld=/2
=2Ld =2*0.5= 1.0m
f=v/ =340/1.0= 340 Hz
(b) 0.5=
f=v/ = 340/0.5= 680 Hz

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