super stuck on this question. please include all equations and steps.. really st
ID: 585510 • Letter: S
Question
super stuck on this question. please include all equations and steps.. really struggling with this chapter in general..
A 5.83 kg block located on a horizontal floor is pulled by a cord that exerts a force F = 10.9 N at an angle ? = 24.2° above the horizontal, as shown in the Figure. The coefficient of kinetic friction between the block and the floor is 0.17.
What is the acceleration of the block?
What is the speed of the block 4.2 s after it starts moving?
A 5.83 kg block located on a horizontal floor is pulled by a cord that exerts a force F 10.9 N at an angle 24.2 above the horizontal, as sho wn in the Figure. The coefficient kinetic friction between the block and the floor is 0.17. What is the normal force between the block and the floor? 48.25N Incorrect. Tries 5/5 Previous Tries What is the acceleration of the block? 1.69m/s 2 1.69m/sA2 Submit Answer Incorrect. Tries 4/5 Previous Tries What is the speed of the block 4.2 s after it starts moving? .158m/s Submit Answer Incorrect. Tries 2/5 Previous TriesExplanation / Answer
a)
Normal force acting on block, N = m*g - F*sin(24.2)
= 5.83*9.8 - 10.9*sin(24.2)
= 52.66 N
Apply,
Fnet = F*cos(thet) - N*mue_k
m*a = 10.9*cos(24.2) - 52.66*0.17
a = 10.9*cos(24.4)/5.83 - 52.66*0.17/5.83
= 0.167 m/s^2 <<<<<<<<<-----------Answer
b) Apply kinematic equation, v = u + a*t
= 0 + 0.167*4.2
= 0.7 m/s <<<<<<<<<-----------Answer
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