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(25%) Problem 3: A conducting spherical shell of inner radius R1 and outer radiu

ID: 584679 • Letter: #

Question

(25%) Problem 3: A conducting spherical shell of inner radius R1 and outer radius R2 has a point charge +q located at its center. The spherical shell has a net charge of taq ©theexpertta.com 33% Part (a) Enter an expression for the surface charge density on the inner surface of the spherical shell Grade Summary Deductions Potential 0% 100% HOME Submissions Attempts remaining: 2 (4% per attempt) detailed view 0 BACKSPACE DELCLEAR Submit Hint Feedback I give up! Hints: Feedback: 33% Part(b) Enter an expression for the surface charge density on the outer surface of the spherical shell. 33% Part (c) The electric field at the surface points radially outward and has a magnitude of 5200 N/C. If R 0.5 m, R2-1.8 m, and a - what is ain coulomhs?

Explanation / Answer

(A)
The charge in the shell will distribute itself on the inner and outer surfaces in such a way that the field inside the conductor is zero.
Charge on the inner surface must be -q ,to cancel the charge +q in the center.

Therefore,
Surface Charge Density of the inner surface, = -q/(4*pi*R1^3)

(B)
Total Charge on the Outer Surface, = (aq+q)
Surface Charge Density of the outer surface, = (aq+q)/ (4*pi*R2^3)

(C)
According to Gauss Law,
E = k*Q/r^2
5200 = (8.9*10^9 * Q) / (1.8)^2
Q = 1.89* 10^-6

aq+q = 1.89* uC
3*q + q = 1.89 uC
q = 0.473 uC