To better understand the concept of static equilibrium a laboratory procedure as

Question

To better understand the concept of static equilibrium a laboratory procedure asks the student to make a calculation before performing the experiment. The apparatus consists of a round level table in the center of which is a massless ring. There are three strings tied to different spots on the ring. Each string passes parallel over the table and is individually strung over a frictionless pulley (there are three pulleys) where a mass is hung. The table is degree marked to indicate the position or angle of each string. There is a mass m1 = 0.161 kg located at 1 = 28.5° and a second mass m2 = 0.215 kg located at 2 = 287°. Calculate the mass m3, and location (in degrees), 3, which will balance the system and the ring will remain stationary.

Explanation / Answer

F1 = m1*g = 0.161kg*9.81m/s^2 = 1.57941N @ 28.5 deg = 1.388i + 0.7536k

F2 = m2*g = 0.215kg*9.81m/s^2 = 2.11N @ 287 deg = 0.617i - 2.0178k

F1 + F2 = 0.771i - 1.2642k = 1.480N @ -58.62 deg (301.38 deg)

so required F3 is 1.480N @ -58.62 +180 deg = 121.38 deg

m3 = 1.480N / 9.81 = 0.151 kg at angle 121.38 deg...........Ans.

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.