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A capacitor consists of two charged disks of radius 4.5 m separated by a distanc

ID: 581352 • Letter: A

Question

A capacitor consists of two charged disks of radius 4.5 m separated by a distances s = 2 mm (see the figure). The magnitude of the charge on each disk is 56 meuC. Consider points A, B, C, and D inside the capacitor, as shown in the diagram. The distance s_1 = 1.2 mm, and the distance s_2 = 0.5 mm. (Assume the +x axis is to the right, the +y axis is up, and the +z axis is out.) What is the electric field inside the capacitor? First, calculate the potential difference V_B - V_A. What is delta l vector along this path? What is V_B - V_A? Next , calculate the potential difference V_C - V_B What is delta l vector along this path? What is V_C - V_B? Finally, calculate the potential difference V_A - V_C. What is delta l vector along this path? What is V_A - V_C?

Explanation / Answer

a) E = Q/(A*epsilon)

= Q/(pi*r^2*epsilon)

= 56*10^-6/(pi*4.5^2*8.854*10^-12)

= 99420 N/c

b) vB - vA = E*s1

= 99420*1.3*10^-3

= 129.25 volts

delta_l = 1.3*10^-3 m

vB - vA = 129.25 volts

c) VC - VB = 0

delta_l = s2

= 0.5 mm

= 5*10^-4 m

Vc - VB = 0

d) VA - VC = vA - vB

= -129.25 volts

delta_l = sqrt(s1^2 + s2^2)

= sqrt(1.3^2 + 0.5^2)

= 1.393 mm

= 1.393*10^-3 m

vA - VC = -129.25 volts